Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 85


$\displaystyle \sum_{i=1}^{7}\frac{i^2}{(i+1)!}$

Work Step by Step

$\frac{1^2}{2}+\frac{2^2}{6}+\frac{3^2}{24}+\frac{4^2}{120}+...+\frac{7^2}{40,320}=\frac{1^2}{(1+1)!}+\frac{2^2}{(2+1)!}+\frac{1^2}{(3+1)!}+\frac{1^2}{(4+1)!}+...+\frac{7^2}{(7+1)!}=\displaystyle \sum_{i=1}^{7}\frac{i^2}{(i+1)!}$
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