Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 60

Answer

$a_0=1$ $a_1=\frac{1}{2}$ $a_2=\frac{1}{6}$ $a_3=\frac{1}{24}$ $a_4=\frac{1}{120}$

Work Step by Step

$a_n=\frac{1}{(n+1)!}$ $a_0=\frac{1}{(0+1)!}=\frac{1}{1}=1$ $a_1=\frac{1}{(1+1)!}=\frac{1}{2!}=\frac{1}{2}$ $a_2=\frac{1}{(1+2)!}=\frac{1}{3!}=\frac{1}{6}$ $a_3=\frac{1}{(1+3)!}=\frac{1}{4!}=\frac{1}{24}$ $a_4=\frac{1}{(1+4)!}=\frac{1}{5!}=\frac{1}{120}$
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