Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 81


$\displaystyle \sum_{i=1}^{8}[2(\frac{i}{8})+3]$

Work Step by Step

$[2(\frac{1}{8})+3]+[2(\frac{2}{8})+3]+...+[2(\frac{8}{8})+3]=\displaystyle \sum_{i=1}^{8}[2(\frac{i}{8})+3]$
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