Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 83


$\displaystyle \sum_{i=1}^{6}(-1)^{i+1}(3)^i$

Work Step by Step

$3-9+27-81+243-729=(-1)^{1+1}(3)^1+(-1)^{2+1}(3)^2+(-1)^{3+1}(3)^3+(-1)^{4+1}(3)^4+(-1)^{5+1}(3)^5+(-1)^{6+1}(3)^6=\displaystyle \sum_{i=1}^{6}(-1)^{i+1}(3)^i$
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