Answer
$\displaystyle \sum_{i=1}^{4}[(i-1)^2+(i+1)^3]=230$
Work Step by Step
$\displaystyle \sum_{i=1}^{4}[(i-1)^2+(i+1)^3]=[(1-1)^2+(1+1)^3]+[(2-1)^2+(2+1)^3]+[(3-1)^2+(3+1)^3]+[(4-1)^2+(4+1)^3=8+28+68+134=230$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 72
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