Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 72


$\displaystyle \sum_{i=1}^{4}[(i-1)^2+(i+1)^3]=230$

Work Step by Step

$\displaystyle \sum_{i=1}^{4}[(i-1)^2+(i+1)^3]=[(1-1)^2+(1+1)^3]+[(2-1)^2+(2+1)^3]+[(3-1)^2+(3+1)^3]+[(4-1)^2+(4+1)^3=8+28+68+134=230$
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