Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Section 13.3 - Solving Nonlinear Systems of Equations - Exercise Set - Page 948: 8

Answer

$(-\sqrt 8, -1)$, $(-\sqrt 8, 1)$, $(\sqrt 8, -1)$, $(\sqrt 8, 1)$

Work Step by Step

$4x^2+3y^2=35$ $5x^2+2y^2=42$ $5x^2+2y^2-(4x^2+3y^2)=42-35$ $x^2-y^2=7$ $x^2-y^2+y^2=7+y^2$ $x^2=7+y^2$ $4x^2+3y^2=35$ $4(7+y^2)+3y^2=35$ $28+4y^2+3y^2=35$ $28+7y^2=35$ $28+7y^2-28=35-28$ $7y^2=7$ $7y^2/7=7/7$ $y^2=1$ $\sqrt {y^2}= \sqrt 1$ $y= ±1$ $y=1$ $4x^2+3y^2=35$ $4x^2+3*1^2=35$ $4x^2+3*1=35$ $4x^2+3=35$ $4x^2+3-3=35-3$ $4x^2=32$ $4x^2/4=32/4$ $x^2=8$ $\sqrt {x^2} =\sqrt 8$ $x = ±\sqrt 8$ Please see the graph to show that the four points are all answers to the system. Red equation: $4x^{2}+3y^{2}=35$ Purple equation: $5x^{2}+2y^{2}=42$
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