Chapter 13 - Section 13.3 - Solving Nonlinear Systems of Equations - Exercise Set - Page 948: 13

${(-5, 25), (2,4)}$

$y=x^2$ $3x+y=10$ $3x+y=10$ $3x+x^2=10$ $x^2+3x-10=10-10$ $x^2+3x-10=0$ $(x+5)(x-2)=0$ $x+5=0$ $x+5-5=0-5$ $x=-5$ $x-2=0$ $x-2+2=0+2$ $x=2$ $x=-5$ $y=x^2$ $y=(-5)^2$ $y=25$ $x=2$ $y=x^2$ $y=2^2$ $y=4$