Answer
$(-1,0)$
Work Step by Step
$y=x+1$
$x^2-y^2=1$
$x^2-y^2=1$
$x^2-(x+1)^2=1$
$x^2-(x*x+x*1+1*x+1*1)=1$
$x^2-(x^2+2x+1)=1$
$x^2-x^2-2x-1=1$
$-2x-1=1$
$-2x-1+1=1+1$
$-2x=2$
$-2x/-2=2/-2$
$x=-1$
$y=x+1$
$y=-1+1$
$y=0$
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