Answer
No solution
Work Step by Step
$x^2+y^2=1$
$y=x^2-9$
$y=x^2-9$
$y+9=x^2-9+9$
$y+9=x^2$
$x^2+y^2=1$
$y+9+y^2=1$
$y^2+y+9-1=1-1$
$y^2+y+8=0$
$a=1$, $b=1$, $c=8$
$x=(-b±\sqrt {b^2-4ac})/2a$
$x=(-1±\sqrt {1^2-4*1*8})/2*1$
$x=(-1±\sqrt {1-32})/2$
$x=(-1±\sqrt {-31})/2$
Since we are looking for the square root of a negative number, we don’t have a solution for this system of equations.