Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Section 13.3 - Solving Nonlinear Systems of Equations - Exercise Set - Page 948: 26

Answer

${(-5,0), (4,-3), (4,3)}$

Work Step by Step

$x^2+y^2=25$ $x=y^2-5$ $x=y^2-5$ $x+5=y^2-5+5$ $x+5=y^2$ $x^2+y^2=25$ $x^2+x+5=25$ $x^2+x+5-25=25-25$ $x^2+x-20=0$ $(x+5)(x-4)=0$ $x+5=0$ $x+5-5=0-5$ $x=-5$ $x-4=0$ $x-4+4=0+4$ $x=4$ $x=-5$ $x^2+y^2=25$ $(-5)^2+y^2=25$ $25+y^2=25$ $25+y^2-25=-25-25$ $y^2=0$ $\sqrt {y^2} =\sqrt 0$ $y=0$ $x=4$ $x^2+y^2=25$ $4^2+y^2=25$ $16+y^2=25$ $16+y^2-16=25-16$ $y^2=9$ $\sqrt {y^2} =\sqrt 9$ $y=±3$
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