Answer
${(-1, -2), (-1,2), (1,-2), (1,2)}$
Work Step by Step
$2x^2+3y^2=14$
$-x^2+y^2=3$
$-x^2+y^2=3$
$2*(-x^2+y^2=3)$
$-2x^2+2y^2=6$
$2x^2+3y^2=14$
$-2x^2+2y^2=6$
$2x^2+3y^2+(-2x^2+2y^2)=14+6$
$2x^2+3y^2-2x^2+2y^2=20$
$5y^2=20$
$5y^2/5=20/5$
$y^2=4$
$\sqrt {y^2} =\sqrt 4$
$y=±2$
$2x^2+3y^2=14$
$2x^2+3*4=14$
$2x^2+12=14$
$2x^2+12-12=14-12$
$2x^2=2$
$2x^2/2=2/2$
$x^2=1$
$\sqrt {x^2} =sqrt 1$
$x=±1$