Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Section 13.3 - Solving Nonlinear Systems of Equations - Exercise Set - Page 948: 30

Answer

${(-4, 0), (0, 4), (4,0)}$

Work Step by Step

$x^2+y^2=16$ $y=-1/4*x^2+4$ $y=-1/4*x^2+4$ $y-4=-1/4*x^2+4-4$ $y-4=-1/4*x^2$ $-4*(y-4)=-4*-1/4*x^2$ $-4y+16=x^2$ $x^2+y^2=16$ $(-4y+16)+y^2=16$ $y^2-4y+16=16$ $y^2-4y+16-16=16-16$ $y^2-4y=0$ $y(y-4)=0$ $y=0$ $y-4=0$ $y-4+4=0+4$ $y=4$ $y=0$ $x^2+y^2=16$ $x^2+0^2=16$ $x^2+0=16$ $x^2=16$ $\sqrt {x^2} =\sqrt {16}$ $x =±4$ $y=4$ $x^2+y^2=16$ $x^2+4^2=16$ $x^2+16=16$ $x^2+16-16=16-16$ $x^2=0$ $\sqrt {x^2} = \sqrt 0$ $x=0$
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