Answer
${(-4, -1), (-4, 1)}$
Work Step by Step
$x=-y^2-3$
$x=y^2-5$
$-y^2-3=y^2-5$
$-y^2-3+y^2+5=y^2-5+y^2+5$
$2=2y^2$
$2/2=2y^2/2$
$1=y^2$
$\sqrt 1 =\sqrt {y^2}$
$y=±1$
$x=y^2-5$
$x=1-5$
$x=-4$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.