Answer
The solution is at (1, -3).
See Graph I for the graphing of the solution.
Work Step by Step
$y = x^2 - 4 \longrightarrow (i)$
$y = x^2 - 4x \longrightarrow (ii)$
$(ii) - (i)$, we have
$0 = 0 -4x + 4$
$4x = 4$
$x = 1$
From $(i)$, when $x = 1$, $y = -3$
The 2 equations intersect at (1, -3).
See Graph I for the graphing of the solution.