Answer
The solution is at (-2, 1).
See Graph I for the graphing of the solution.
Work Step by Step
$x = y^2 - 3 \longrightarrow (i)$
$x = y^2 - 3y \longrightarrow (ii)$
$(ii) - (i)$, we have
$0 = 0 -3y + 3$
$3y = 3$
$y = 1$
From $(i)$, when $y = 1$, $x = -2$
The 2 equations intersect at (-2, 1).
See Graph I for the graphing of the solution.