Answer
${(-\sqrt 3, -\sqrt 5), (-\sqrt 3, \sqrt 5), (\sqrt 3, -\sqrt 5), (\sqrt 3, \sqrt 5)}$
Work Step by Step
$4x^2-2y^2=2$
$-x^2+y^2=2$
$-x^2+y^2=2$
$2*(-x^2+y^2=2)$
$-2x^2+2y^2=4$
$4x^2-2y^2=2$
$-2x^2+2y^2=4$
$4x^2-2y^2+(-2x^2+2y^2)=2+4$
$4x^2-2y^2-2x^2+2y^2=6$
$2x^2=6$
$2x^2/2=6/2$
$x^2=3$
$\sqrt {x^2} =\sqrt 3$
$x= ±\sqrt 3$
$4x^2-2y^2=2$
$4*3-2y^2=2$
$12-2y^2=2$
$12-2y^2+2y^2-2=2+2y^2-2$
$10=2y^2$
$10/2=2y^2/2$
$5=y^2$
$\sqrt 5 = \sqrt {y^2}$
$y = ±\sqrt 5$
