Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Practice and Problem-Solving Exercises - Page 386: 66

Answer

$\dfrac{y^{5}}{x^{10}}$

Work Step by Step

Here, we have a fraction raised to a power. This means that the exponent applies to both the numerator and the denominator. When we raise a power to a power, we simply multiply the two powers together: $\dfrac{x^{(-2/3)(15)}}{y^{(-1/3)(15)}}=\dfrac{x^{-30/3}}{y^{-15/3}}=\dfrac{x^{-10}}{y^{-5}}$ Simplified expressions cannot have negative exponents. To get rid of the negative exponent, use the rule $a^{-m}=\frac{1}{a^m}$ to obtain: $$\dfrac{x^{-10}}{y^{-5}}=\dfrac{\frac{1}{x^{10}}}{\frac{1}{y^5}}=\frac{1}{x^{10}} \cdot \frac{y^{5}}{1}=\dfrac{y^5}{x^{10}}$$
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