Answer
$\dfrac{5x^{1/3}}{x}$
Work Step by Step
When we raise a power to a power, we simply multiply the two powers together:
$5(x^{2/3})^{-1}$ = $5x^{(2/3)(-1)}$
Simplify the power by multiplying them together:
$=5x^{-2/3}$
Simplified expressions cannot have negative exponents.
To get rid of the negative exponent, use the rule $a^{-m}=\frac{1}{a^m}$ to obtain:
$$=5\cdot \frac{1}{x^{2/3}}\\
=\frac{5}{x^{2/3}}$$
We also should not have fractional exponent in the denominator, so to get rid of this, we will multiply both numerator and denominator by an exponential expression with the same base but with an exponent that, when added to the original fractional exponent, will give $1$:
$=\left(\dfrac{5}{x^{2/3}}\right)\left(\dfrac{x^{1/3}}{x^{1/3}}\right)$
$=\dfrac{5x^{1/3}}{x^{2/3 + 1/3}}$
$=\dfrac{5x^{1/3}}{x^{3/3}}$
$=\dfrac{5x^{1/3}}{x^{1}}$
$=\dfrac{5x^{1/3}}{x}$
