Answer
$\left(7x^3\right)^{\frac{1}{2}}$
Work Step by Step
Recall the rational exponent property (pg. 382):
$\sqrt[n]{a}=a^{\frac{1}{n}}$
Applying this property ($n=2$), we get:
$\sqrt{7x^3}=\left(7x^3\right)^{\frac{1}{2}}$
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