Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Practice and Problem-Solving Exercises - Page 386: 45

Answer

$\dfrac{\sqrt[6]{7,776}}{6}$

Work Step by Step

Using $\sqrt[n]{x^m}=x^{\frac{m}{n}},$ the given expression, $ \dfrac{\sqrt[]{6}}{\sqrt[3]{36}} ,$ is equivalent to \begin{align*} & \dfrac{\sqrt[]{6}}{\sqrt[3]{6^2}} \\\\&= \dfrac{6^{\frac{1}{2}}}{6^{\frac{2}{3}}} .\end{align*} Using the laws of exponents, the expression above is equivalent to \begin{align*} & 6^{\frac{1}{2}-\frac{2}{3}} &\left( \text{use }\dfrac{a^{x}}{a^y}=a^{x-y} \right) \\\\&= 6^{\frac{3}{6}-\frac{4}{6}} \\\\&= 6^{-\frac{1}{6}} \\\\&= \dfrac{1}{6^{\frac{1}{6}}} &\left( \text{use }a^{-x}=\dfrac{1}{a^x} \right) \\\\&= \dfrac{1}{\sqrt[6]{6^1}} \\\\&= \dfrac{1}{\sqrt[6]{6}} \\\\&= \dfrac{1}{\sqrt[6]{6}}\cdot\dfrac{\sqrt[6]{6^5}}{\sqrt[6]{6^5}} &\left( \text{rationalize denominator} \right) \\\\&= \dfrac{\sqrt[6]{6^5}}{\sqrt[6]{6^6}} \\\\&= \dfrac{\sqrt[6]{7,776}}{6} .\end{align*} Hence, the simplified form of the given expression is $ \dfrac{\sqrt[6]{7,776}}{6} .$
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