Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Practice and Problem-Solving Exercises - Page 386: 50

Answer

$64$

Work Step by Step

Since $(-2)^5=-32$, then: $(-32)^{\frac{6}{5}}=\left[(-2)^5\right]^{\frac{6}{5}}$ Now, recall the basic exponent property (pg. 360): $(a^m)^n=a^{mn}$ Applying this property, we get: \begin{align*} \left[(-2)^5\right]^{\frac{6}{5}}&=(-2)^{\frac{5\cdot6}{5}}\\ &=(-2)^{\frac{30}{5}}\\ &=(-2)^6 &=64 \end{align*}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.