Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Practice and Problem-Solving Exercises - Page 386: 44

Answer

$6\sqrt[4]{2}$

Work Step by Step

Since $\sqrt{12}$ is equivalent to $\sqrt[4]{12^2},$ the given expression, $ \sqrt[4]{18}\cdot\sqrt[]{12} ,$ is equivalent to \begin{align*} & \sqrt[4]{18}\cdot\sqrt[4]{12^2} .\end{align*} Using the laws of exponents, the expression above is equivalent to \begin{align*} & \sqrt[4]{18(12)^2} &\left( \text{use }\sqrt{a}\cdot \sqrt{b}=\sqrt{ab} \right) \\\\&= \sqrt[4]{(9\cdot2)(3\cdot4)^2} \\\\&= \sqrt[4]{(3^2\cdot2)(3\cdot2^2)^2} \\\\&= \sqrt[4]{(3^2\cdot2)(3^2\cdot2^4)} &\left( \text{use }(a^x)^y=a^{xy} \right) \\\\&= \sqrt[4]{3^{2+2}\cdot2^{1+4}} &\left( \text{use }a^x\cdot a^y=a^{x+y} \right) \\\\&= \sqrt[4]{3^{4}\cdot2^{5}} \\\\&= \sqrt[4]{3^{4}\cdot2^{4}\cdot2^1} \\\\&= \sqrt[4]{(3\cdot2)^{4}\cdot2} \\\\&= (3\cdot2)\sqrt[4]{2} \\\\&= 6\sqrt[4]{2} .\end{align*} Hence, the simplified form of the given expression is $ 6\sqrt[4]{2} .$
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