Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Practice and Problem-Solving Exercises - Page 386: 27

Answer

$(-10)^{\frac{1}{2}}$

Work Step by Step

We are asked to replace radicals with exponents in the given equation: $\sqrt{-10}$ Recall the rational exponent property (pg. 382): $\sqrt[n]{a}=a^{\frac{1}{n}}$ Applying this property, we get: $\sqrt{-10}=\sqrt[2]{-10}=(-10)^{\frac{1}{2}}$
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