Answer
$3$
Work Step by Step
Recall the basic exponent property (pg. 360):
$(ab)^n=a^nb^n$
Applying this property to the given expression gives:
$=(3\cdot27)^{\frac{1}{4}}$
$=81^{\frac{1}{4}}$
Recall that $\sqrt[n]{x}=x^{\frac{1}{n}}$
Applying this property, to the expression above results to:
$=\sqrt[4]{81}\\
=\sqrt[4]{3^4}$
$=3$