Answer
$3$
Work Step by Step
Recall that $\sqrt[n]{x}=x^{\frac{1}{n}}$.
We change the exponent to a radical:
$27^{\frac{1}{3}}=\sqrt[3]{27}$
Recall that $3^3=27$.
Thus,
$\sqrt[3]{27}=\sqrt[3]{3^3}=3$
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