Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Practice and Problem-Solving Exercises - Page 386: 11

Answer

$3$

Work Step by Step

Recall that $\sqrt[n]{x}=x^{\frac{1}{n}}$. We change the exponent to a radical: $27^{\frac{1}{3}}=\sqrt[3]{27}$ Recall that $3^3=27$. Thus, $\sqrt[3]{27}=\sqrt[3]{3^3}=3$
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