Answer
$7$
Work Step by Step
Recall that $\sqrt[n]{x}=x^{\frac{1}{n}}$.
We change the exponent to a radical:
${49}^{\frac{1}{2}}=\sqrt[2]{49}$
Recall that $7^2=49$.
Thus,
$\sqrt{49}=\sqrt{7^2}=7$
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