Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-4 Rational Exponents - Practice and Problem-Solving Exercises - Page 386: 41

Answer

$\sqrt[10]{5^{7}}$

Work Step by Step

Recall the rational exponent property (pg. 382): $\sqrt[n]{a}=a^{\frac{1}{n}}$ Applying this property, we get: $\left(\sqrt[3]5\right)\left(\sqrt[5]5\right)=\left(5^{\frac{1}{2}}\right)\left(5^{\frac{1}{5}}\right)$ Next, recall the basic exponent property (pg. 360): $a^ma^n=a^{m+n}$ Applying this property to our last equation, we get: \begin{align*} \left(5^{\frac{1}{2}}\right)\left(5^{\frac{1}{5}}\right)&=5^{\frac{1}{2}+\frac{1}{5}}\\ &=5^{\frac{5}{10}+\frac{2}{10}}\\ &=5^{\frac{5+2}{10}}\\ &=5^{\frac{7}{10}} \end{align*} Now, recall the rational exponent property (pg. 382): $a^{\frac{m}{n}}=\sqrt[n]{a^m}=(\sqrt[n]{a})^m$ We use this property to rewrite the result as a radical: $5^{\frac{7}{10}}=\sqrt[10]{5^{7}}$
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