Answer
$\dfrac{3x^2}{10\sqrt[3]{9x}}$
Work Step by Step
Rationalizing the numerator of $
\dfrac{\sqrt[3]{3x^5}}{10}
$ results to
\begin{array}{l}
\dfrac{\sqrt[3]{3x^5}}{10}
\cdot
\dfrac{\sqrt[3]{9x}}{\sqrt[3]{9x}}
\\\\=
\dfrac{\sqrt[3]{27x^6}}{10\sqrt[3]{9x}}
\\\\=
\dfrac{3x^2}{10\sqrt[3]{9x}}
.\end{array}