Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 55

Answer

$\dfrac{5}{\sqrt{15}}$

Work Step by Step

Rationalizing the numerator of $ \sqrt{\dfrac{5}{3}} $ results to \begin{array}{l} \sqrt{\dfrac{5}{3}} \cdot \sqrt{\dfrac{5}{5}} \\\\= \sqrt{\dfrac{25}{15}} \\\\= \dfrac{5}{\sqrt{15}} .\end{array}
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