Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 17

Answer

$\dfrac{2\sqrt[]{21}}{7}$

Work Step by Step

Rationalizing the denominator of $ \dfrac{2\sqrt{3}}{\sqrt[]{7}} $ results to \begin{array}{l} \dfrac{2\sqrt{3}}{\sqrt[]{7}} \cdot \dfrac{\sqrt[]{7}}{\sqrt[]{7}} \\\\= \dfrac{2\sqrt[]{21}}{\sqrt[]{49}} \\\\= \dfrac{2\sqrt[]{21}}{7} .\end{array}
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