Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 60

Answer

$\dfrac{x^3}{2\sqrt{3x}}$

Work Step by Step

Rationalizing the numerator of $ \dfrac{\sqrt{3x^5}}{6} $ results to \begin{array}{l} \dfrac{\sqrt{x^4\cdot3x}}{6} \\\\= \dfrac{x^2\sqrt{3x}}{6} \\\\= \dfrac{x^2\sqrt{3x}}{6} \cdot \dfrac{\sqrt{3x}}{\sqrt{3x}} \\\\= \dfrac{x^2\sqrt{9x^2}}{6\sqrt{3x}} \\\\= \dfrac{x^2\cdot3x}{6\sqrt{3x}} \\\\= \dfrac{3x^3}{6\sqrt{3x}} \\\\= \dfrac{x^3}{2\sqrt{3x}} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.