Answer
$\dfrac{5\sqrt[3]{3}}{3}$
Work Step by Step
Rationalizing the denominator of $
\dfrac{5}{\sqrt[3]{9}}
$ results to
\begin{array}{l}
\dfrac{5}{\sqrt[3]{9}}
\cdot
\dfrac{\sqrt[3]{3}}{\sqrt[3]{3}}
\\\\=
\dfrac{5\sqrt[3]{3}}{\sqrt[3]{27}}
\\\\=
\dfrac{5\sqrt[3]{3}}{3}
.\end{array}