Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 15

Answer

$\dfrac{3\sqrt[3]{4}}{2}$

Work Step by Step

Rationalizing the denominator of $ \dfrac{3}{\sqrt[3]{2}} $ results to \begin{array}{l} \dfrac{3}{\sqrt[3]{2}} \cdot \dfrac{\sqrt[3]{4}}{\sqrt[3]{4}} \\\\= \dfrac{3\sqrt[3]{4}}{\sqrt[3]{8}} \\\\= \dfrac{3\sqrt[3]{4}}{2} .\end{array}
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