Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 445: 59

Answer

$\dfrac{2x}{7\sqrt{x}}$

Work Step by Step

Rationalizing the numerator of $ \dfrac{\sqrt{4x}}{7} $ results to \begin{array}{l} \dfrac{2\sqrt{x}}{7} \\\\= \dfrac{2\sqrt{x}}{7} \cdot \dfrac{\sqrt{x}}{\sqrt{x}} \\\\= \dfrac{2\sqrt{x^2}}{7\sqrt{x}} \\\\= \dfrac{2x}{7\sqrt{x}} .\end{array}
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