Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 62

Answer

$\dfrac{2x}{z\sqrt[3]{2x^2z}}$

Work Step by Step

Rationalizing the numerator of $ \dfrac{\sqrt[3]{4x}}{\sqrt[3]{z^4}} $ results to \begin{array}{l} \dfrac{\sqrt[3]{4x}}{z\sqrt[3]{z}} \cdot \dfrac{\sqrt[3]{2x^2}}{\sqrt[3]{2x^2}} \\\\= \dfrac{\sqrt[3]{8x^3}}{z\sqrt[3]{2x^2z}} \\\\= \dfrac{2x}{z\sqrt[3]{2x^2z}} .\end{array}
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