Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 23

Answer

$\dfrac{\sqrt{6x}}{10}$

Work Step by Step

Rationalizing the denominator of $ \sqrt[]{\dfrac{3x}{50}} $ results to \begin{array}{l} \sqrt[]{\dfrac{3x}{50}} \cdot \sqrt[]{\dfrac{2}{2}} \\\\= \sqrt[]{\dfrac{6x}{100}} \\\\= \dfrac{\sqrt{6x}}{10} .\end{array}
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