## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 65

#### Answer

$\dfrac{2x}{11\sqrt{2x}}$

#### Work Step by Step

Rationalizing the numerator of $\dfrac{\sqrt{2x}}{11}$ results to \begin{array}{l} \dfrac{\sqrt{2x}}{11} \cdot \dfrac{\sqrt{2x}}{\sqrt{2x}} \\\\= \dfrac{\sqrt{4x^2}}{11\sqrt{2x}} \\\\= \dfrac{2x}{11\sqrt{2x}} .\end{array}

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