Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 445: 65

Answer

$\dfrac{2x}{11\sqrt{2x}}$

Work Step by Step

Rationalizing the numerator of $ \dfrac{\sqrt{2x}}{11} $ results to \begin{array}{l} \dfrac{\sqrt{2x}}{11} \cdot \dfrac{\sqrt{2x}}{\sqrt{2x}} \\\\= \dfrac{\sqrt{4x^2}}{11\sqrt{2x}} \\\\= \dfrac{2x}{11\sqrt{2x}} .\end{array}
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