Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 445: 5

Answer

$\frac{2\sqrt x}{x}$

Work Step by Step

$\sqrt \frac{4}{x}=\frac{\sqrt 4}{\sqrt x}=\frac{\sqrt4 \times \sqrt x}{\sqrt x \times \sqrt x}=\frac{2\sqrt x}{x}$ We know that $\sqrt 4=2$, because $2^{2}=4$.
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