Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 6

Answer

$\frac{5\sqrt y}{y}$

Work Step by Step

$\sqrt \frac{25}{y}=\frac{\sqrt 25}{\sqrt y}=\frac{\sqrt25 \times \sqrt y}{\sqrt y \times \sqrt y}=\frac{5\sqrt y}{y}$ We know that $\sqrt 25=5$, because $5^{2}=25$.
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