Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set: 70

Answer

$\dfrac{3y}{\sqrt[3]{21y^2}}$

Work Step by Step

Rationalizing the numerator of $ \sqrt[3]{\dfrac{9y}{7}} $ results to \begin{array}{l} \sqrt[3]{\dfrac{9y}{7}} \cdot \sqrt[3]{\dfrac{3y^2}{3y^2}} \\\\= \sqrt[3]{\dfrac{27y^3}{21y^2}} \\\\= \dfrac{3y}{\sqrt[3]{21y^2}} .\end{array}
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