Chapter 7 - Section 7.5 - Rationalizing Denominators and Numerators of Radical Expressions - Exercise Set - Page 445: 68

$\dfrac{5}{\sqrt[3]{10}}$

Rationalizing the numerator of $ \sqrt[3]{\dfrac{25}{2}} $ results to \begin{array}{l} \sqrt[3]{\dfrac{25}{2}} \cdot \sqrt[3]{\dfrac{5}{5}} \\\\= \sqrt[3]{\dfrac{125}{10}} \\\\= \dfrac{5}{\sqrt[3]{10}} .\end{array}