Answer
$\dfrac{\sqrt[3]{75}}{5}$
Work Step by Step
Rationalizing the denominator of $
\sqrt[3]{\dfrac{3}{5}}
$ results to
\begin{array}{l}
\sqrt[3]{\dfrac{3}{5}}
\cdot
\sqrt[3]{\dfrac{5^2}{5^2}}
\\\\=
\sqrt[3]{\dfrac{3\cdot5^2}{5^3}}
\\\\=
\dfrac{\sqrt[3]{75}}{5}
.\end{array}