Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 94

Answer

$(-\frac{2}{5},\frac{1}{10})$

Work Step by Step

We know that the midpoint of the line segment whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is the point with coordinates $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$. Therefore, a line with endpoints $(-\frac{2}{5},\frac{7}{15})$ and $(-\frac{2}{5},-\frac{4}{15})$ will have a midpoint of $(\frac{-\frac{2}{5}+(-\frac{2}{5})}{2},\frac{\frac{7}{15}+(-\frac{4}{15})}{2})=(\frac{-\frac{4}{5}}{2},\frac{\frac{3}{15}}{2})=(\frac{-\frac{4}{5}}{2},\frac{\frac{1}{5}}{2})=(-\frac{2}{5},\frac{1}{10})$.
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