Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 58

Answer

$2a^{2}b^{3}$

Work Step by Step

$\sqrt [3](8a^{6}b^{9})=\sqrt[3] (8\times a^{6} \times b^{9})=\sqrt[3] 8\times \sqrt[3] (a^{6})\times \sqrt [3](b^{9})=2a^{2}b^{3}$ We know that $\sqrt[3] 8=2$, because $2^{3}=8$. We also know that $\sqrt[3] (a^{6})=a^{2}$, because $(a^{2})^{3}=a^{2\times3}=a^{6}$ and that $\sqrt[3] (b^{9})=b^{3}$, because $(b^{3})^{3}=b^{3\times3}=b^{9}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.