Answer
$x^{2}-8x+16$
Work Step by Step
We are given the expression $(x-4)^{2}$, which is equivalent to $(x-4)(x-4)$. We can use the FOIL method to simplify.
F=$x\times x=x^{2}$
O= $x\times-4=-4x$
I=$-4\times x=-4x$
L=$-4\times-4=16$
Now, we can add these terms together.
$(x-4)^{2}=(x^{2})+(-4x)+(-4x)+(16)=x^{2}-8x+16$