Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 36

Answer

$6\sqrt 2$

Work Step by Step

$3\sqrt 8=3\times\sqrt 4\times\sqrt 2=(3\times2)\times\sqrt 2=6\sqrt 2$ We know that $\sqrt 4=2$, because $2^{2}=4$.
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