Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 37

Answer

$2\sqrt 6$

Work Step by Step

$\sqrt 24=\sqrt (4\times6)=\sqrt 4 \times\sqrt 6=2\sqrt 6$ We know that $\sqrt 4=2$, because $2^{2}=4$.
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