Answer
$2xy^3\sqrt[5]{3x^{2}}$
Work Step by Step
Using the properties of radicals, then,
\begin{array}{l}
\dfrac{\sqrt[5]{192x^{6}y^{12}}}{\sqrt[5]{2x^{-1}y^{-3}}}
\\\\=
\sqrt[5]{\dfrac{192x^{6}y^{12}}{2x^{-1}y^{-3}}}
\\\\=
\sqrt[5]{96x^{6-(-1)}y^{12-(-3)}}
\\\\=
\sqrt[5]{96x^{7}y^{15}}
\\\\=
\sqrt[5]{32x^5y^{15}\cdot3x^{2}}
\\\\=
2xy^3\sqrt[5]{3x^{2}}
.\end{array}
