Answer
$\frac{y\sqrt z}{6}$
Work Step by Step
The quotient rule holds that $\sqrt[n] (\frac{a}{b})=\frac{\sqrt[n] a}{\sqrt[n] b}$ (where $\sqrt[n] a$ and $\sqrt[n] b$ are real numbers and $\sqrt[n] b$ is nonzero).
Therefore, $\sqrt (\frac{y^{2}z}{36})=\frac{\sqrt (y^{2}z)}{\sqrt 36}=\frac{\sqrt (y^{2})\times\sqrt z}{\sqrt 36}=\frac{y\sqrt z}{6}$
We know that $\sqrt (y^{2})=y$, because $(y)^{2}=y^{2}$. Also, we know that $\sqrt 36=6$, because $6^{2}=36$.
