Answer
$(-\frac{3}{2},\frac{11}{2})$
Work Step by Step
We know that the midpoint of the line segment whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is the point with coordinates $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$.
Therefore, a line with endpoints (-2, 5) and (-1, 6) will have a midpoint of $(\frac{-2+(-1)}{2},\frac{5+6}{2})=(-\frac{3}{2},\frac{11}{2})$.
